The network is 172.25.0.0
this network is class B so its default mask is 255.255.0.0
the network portion is 16 bit : 172.25
the host portion is 16 bit : 0.0
to divide this network into 8 subnet and take subnet zero in consideration we have to borrow 3 bit from host portion
3^2 = 8 subnets
So it will be
172.25.00000000.00000000
Network portion Host portion
The First subnet is
172.25.00000000.00000000
Network ID 172.25.0.0 subnet zero
First IP 172.25.0.1
Last Ip 172.25.31.254
Broadcast IP 172.25.31.255
The Second subnet is
172.25.00100000.00000000
Network ID 172.25.32.0
First IP 172.25.32.1
Last Ip 172.25.63.254
Broadcast IP 172.25.63.255
The Third subnet is
172.25.01000000.00000000
Network ID 172.25.64.0
First IP 172.25.64.1
Last Ip 172.25.95.254
Broadcast IP 172.25.95.255
The 4th subnet is
172.25.01100000.00000000
Network ID 172.25.96.0
First IP 172.25.96.1
Last Ip 172.25.127.254
Broadcast IP 172.25.127.255
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and so on
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