QUESTION NO: 9
Which two of the addresses below are available for host addresses on the subnet
192.168.15.19/28? (Select two answer choices)
A. 192.168.15.17
B. 192.168.15.14
C. 192.168.15.29
D. 192.168.15.16
E. 192.168.15.31
F. None of the above


دة السؤال الاول الى شكيت فية هنا فى غلط بالنسبة لية 192.168.15.19/28 يكون subnet المفروض يكون عدد زوجى ولا اية يعنى المفروض الاجابة الامثل f لا هو تزاكى
وبص عملها اية
Answer: A, C
Explanation:
The network uses a 28bit subnet (255.255.255.240). This means that 4 bits are used for
the networks and 4 bits for the hosts. This allows for 14 networks and 14 hosts (2n-2).
The last bit used to make 240 is the 4th bit (16) therefore the first network will be
192.168.15.16. The network will have 16 addresses (but remember that the first address
is the network address and the last address is the broadcast address). In other words, the
networks will be in increments of 16 beginning at 192.168.15.16/28. The IP address we
are given is 192.168.15.19. Therefore the other host addresses must also be on this
network. Valid IP addresses for hosts on this network are: 192.168.15.17-192.168.15.30.
Incorrect Answers:
B. This is not a valid address for this particular 28 bit subnet mask. The first network
address should be 192.168.15.16.
D. This is the network address.
E. This is the broadcast address for this particular subnet




حاجة تانية

QUESTION NO: 12
Leading the way in IT testing and certification tools, www.testking.com
- 35 -
How many subnetworks and hosts are available per subnet if you apply a /28 mask
to the 210.10.2.0 class C network?
A. 30 networks and 6 hosts.
B. 6 networks and 30 hosts.
C. 8 networks and 32 hosts.
D. 32 networks and 18 hosts.
E. 16 networks and 14 hosts.
F. None of the above

هنا المفروض تكون i 14 networks and 14 hosts لان فى اول شبكة واخر شبكة مابيتحسبوش
يعنى المفروض تكون الاجابة f
وكانت اجابتة e
ياريت حد يساعدنى ياجماعةةةةةةةةةةةةةةةةة وجزاكم الله خيرا